In the following circuit,the output Y becomes | vedclass

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(D) The circuit consists of an $AND$ gate followed by a $NAND$ gate. The inputs to the $AND$ gate are $A$ and $B$,so its output is $A \cdot B$.The inp

Vedclass · Accepted Answer

$A=1, B=1, C=0$

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(D) The circuit consists of an $AND$ gate followed by a $NAND$ gate. The inputs to the $AND$ gate are $A$ and $B$,so its output is $A \cdot B$.The input $C$ passes through a $NOT$ gate,so its output is $\bar{C}$.These two signals are the inputs to the $NAND$ gate,which produces the final output $Y$.Thus,$Y = \overline{(A \cdot B) \cdot \bar{C}}$.Using De Morgan's law,$Y = \overline{A \cdot B} + \overline{\bar{C}} = \bar{A} + \bar{B} + C$.For the output $Y$ to be zero $(Y=0)$,we must have $\bar{A} + \bar{B} + C = 0$.This requires $\bar{A} = 0$,$\bar{B} = 0$,and $C = 0$ simultaneously.Therefore,$A = 1$,$B = 1$,and $C = 0$.

$A$	$B$	$X$
$0$	$0$	$0$
$0$	$1$	$1$
$1$	$0$	$1$
$1$	$1$	$1$

In the following circuit,the output $Y$ becomes zero for which of the following input combinations?

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