In the figure shown the electric potential energy of the system is: ( $q$ is at the centre of the conducting neutral spherical shell of inner radius $a$ and outer radius $b$ )
In the figure shown the electric potential energy of the system is: ( $q$ is at the centre of the conducting neutral spherical shell of inner radius $a$ and outer radius $b$ )
- A
$0$
- B
$\frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2b}}}}$
- C
$\frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2b}}}} - \frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2a}}}}$
- D
$\frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2a}}}} - \frac{{{\text{k}}{{\text{q}}^2}}}{{{\text{2b}}}}$
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