In the figure shown,the electric potential en | vedclass

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(C) The system consists of a point charge $q$ at the center,a charge $-q$ induced on the inner surface of the shell (radius $a$),and a charge $+q$ ind

Vedclass · Accepted Answer

$\frac{kq^2}{2b} - \frac{kq^2}{2a}$

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(C) The system consists of a point charge $q$ at the center,a charge $-q$ induced on the inner surface of the shell (radius $a$),and a charge $+q$ induced on the outer surface of the shell (radius $b$).The total potential energy $U$ is the sum of the self-energies of the charges and their interaction energies.$U = U_{	ext{self}} + U_{	ext{interaction}}$$U = \left( \frac{kq^2}{2a} + \frac{kq^2}{2b} ight) + \left( \frac{k(q)(-q)}{a} + \frac{k(q)(q)}{b} + \frac{k(-q)(q)}{b} ight)$$U = \frac{kq^2}{2a} + \frac{kq^2}{2b} - \frac{kq^2}{a} + \frac{kq^2}{b} - \frac{kq^2}{b}$$U = \frac{kq^2}{2b} - \frac{kq^2}{2a}$

In the figure shown,the electric potential energy of the system is: ($q$ is at the centre of the conducting neutral spherical shell of inner radius $a$ and outer radius $b$)

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