The electric field at a place is given by $\overrightarrow{E} = E_0 \hat{i} \text{ V/m}$. $A$ particle of charge $+q_0$ moves from point $A(0, a)$ to point $B(a, 0)$ along a circular path as shown in the figure. Find the work done by the electric field in this motion.

Eleven equal point charges,each of magnitude $+Q$,are placed at all the hour positions of a circular clock of radius $r$,except at the $10$ o'clock position. What is the electric field strength at the centre of the clock?

The electric field due to a charge at a distance of $3\, m$ from it is $500\, N/C$. The magnitude of the charge is $.......\,\mu C$ $\left[ {\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}\,\frac{{N \cdot m^2}}{{C^2}}} \right]$

Infinite charges of magnitude $q$ each are placed at $x = 1, 2, 4, 8, ...$ meters on the $X$-axis. The value of the intensity of the electric field at the point $x = 0$ due to these charges will be:

An infinite number of electric charges, each equal to $5 \text{ nC}$ (magnitude), are placed along the $X$-axis at $x = 1 \text{ cm}, x = 2 \text{ cm}, x = 4 \text{ cm}, x = 8 \text{ cm}, \dots$ and so on. In this setup, if the consecutive charges have opposite signs, then the electric field in $\text{N/C}$ at $x = 0$ is: $\left(\frac{1}{4 \pi \varepsilon_0} = 9 \times 10^9 \text{ N} \cdot \text{m}^2/\text{C}^2\right)$

Obtain the equation of electric field at a point due to a system of $n$ point charges.