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(C) The magnetic field $B$ produced by a long straight current-carrying conductor at a distance $r$ is given by $B = \frac{\mu_0 I}{2 \pi r}$.As the r

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induced electric current is clockwise

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(C) The magnetic field $B$ produced by a long straight current-carrying conductor at a distance $r$ is given by $B = \frac{\mu_0 I}{2 \pi r}$.As the ring falls towards the conductor,the distance $r$ decreases,causing the magnetic field $B$ passing through the ring to increase.According to the right-hand rule,the magnetic field lines from the conductor point out of the plane of the paper in the region where the ring is located.Since the magnetic flux linked with the ring is increasing in the outward direction,according to Lenz's law,the induced current in the ring will create a magnetic field pointing into the plane of the paper to oppose this increase.Using the right-hand grip rule,a magnetic field directed into the plane of the paper corresponds to a clockwise induced current in the ring.

In the figure,a conducting ring of certain resistance is falling towards a current-carrying straight long conductor. The ring and conductor are in the same plane. Then,the:

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