A coil of n turns and resistance R Omega is c | vedclass

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(A) According to Faraday's law of electromagnetic induction,the induced electromotive force $(e)$ in a coil of $n$ turns is given by $e = -n \frac{d\p

Vedclass · Accepted Answer

$\frac{4 n(\phi_1 - \phi_2)}{5 Rt}$

Vedclass · Answer

(A) According to Faraday's law of electromagnetic induction,the induced electromotive force $(e)$ in a coil of $n$ turns is given by $e = -n \frac{d\phi}{dt}$.For a finite change in flux from $\phi_1$ to $\phi_2$ in time $t$,the average induced emf is $|e| = n \frac{|\phi_2 - \phi_1|}{t} = \frac{n(\phi_1 - \phi_2)}{t}$.The total resistance of the circuit is $R_{total} = R + R/4 = \frac{5R}{4}$.Using Ohm's law,the induced current $I$ is given by $I = \frac{|e|}{R_{total}}$.Substituting the values,$I = \frac{n(\phi_1 - \phi_2) / t}{5R / 4} = \frac{4n(\phi_1 - \phi_2)}{5Rt}$.

$A$ coil of $n$ turns and resistance $R \Omega$ is connected in series with a resistance $R/4$. The combination is moved for time $t$ seconds through a magnetic flux change from $\phi_1$ to $\phi_2$. The induced current in the circuit is:

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