In the diagram, $I_1$ , $I_2$ are the strength of the currents in the loop and infinite long straight conductor respectively. $OA = AB = R$ . The net magnetic field at the centre $O$ is zero. Then the ratio of the currents in the loop and the straight conductor is
$\pi $
$2\pi $
$\frac{1}{\pi }$
$\frac{1}{{2\pi }}$
A length $L$ of wire carries a steady current $I$. It is bent first to form a circular plane coil of one turn. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same current is
When equal current is passed through two coils, equal magnetic field is produced at their centres. If the ratio of number of turns in the coils is $8: 15$, then the ratio of their radii will be
Find out magnetic field at point $O$ ?
Write formula for magnetic field at centre of ring.
A cell is connected between two points of a uniformly thick circular conductor. The magnetic field at the centre of the loop will be