A cell is connected between two points of a u | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) Directions of currents in two parts are different, so directions of magnetic fields due to these currents are opposite. Also applying Ohm&rsq

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(a) Directions of currents in two parts are different, so directions of magnetic fields due to these currents are opposite. Also applying Ohm&rsquo;s law across $AB$
${i_1}{R_1} = {i_2}{R_2} \Rightarrow {i_1}{l_2} = {i_2}{l_2}$     $\left( {\;R = ho \frac{l}{A}} ight)$
Also ${B_1} = \frac{{{\mu _o}}}{{4\pi }} 	imes \frac{{{i_1}{l_1}}}{{{r^2}}}$ and ${B_2} = \frac{{{\mu _o}}}{{4\pi }} 	imes \frac{{{i_2}{l_2}}}{{{r^2}}}$    ($\;l = r	heta $)
$	herefore \,\frac{{{B_2}}}{{{B_1}}} = \frac{{{i_1}{l_1}}}{{{i_2}{l_2}}} = 1$
Hence, two field induction&rsquo;s are equal but of opposite direction. So, resultant magnetic induction at the centre is zero and is independent of $	heta $.

A cell is connected between two points of a uniformly thick circular conductor. The magnetic field at the centre of the loop will be

Similar Questions

The magnetic induction at the centre of a current carrying circular coil of radius $10\, cm$ is $5\sqrt 5 \,times$ the magnetic induction at a point on its axis. The distance of the point from the centre of the coil (in $cm$) is

Write proportionality constant of Biot-Savart law with unit and value (magnitude).

Write equation of magnetic field on axis from centre which have distance equal to radius.

Two very long, straight and insulated wires are kept at $90^o$ angle from each other In $xy -$ plane as shown in the figure. These wires carry current of equal magnitude $I$, whose directions are shown in the figure. The net magnetic field at point $P$ will be

Magnetic field at point $'M'$ of given current distribution