In the decay sequence:^{238}_{92}U xrightarro | vedclass

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(A) Analyze the decay sequence:$1$. $^{238}_{92}U \xrightarrow{- x_1} ^{234}_{90}Th$: Mass number decreases by $4$ and atomic number by $2$,so $x_1$ i

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$1, 2, 3$

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(A) Analyze the decay sequence:$1$. $^{238}_{92}U \xrightarrow{- x_1} ^{234}_{90}Th$: Mass number decreases by $4$ and atomic number by $2$,so $x_1$ is an $\alpha$-particle $(^{4}_{2}He^{2+})$. $\alpha$-particles are positively charged and deflect towards the negatively charged plate. Statement $(3)$ is correct.$2$. $^{234}_{90}Th \xrightarrow{- x_2} ^{234}_{91}Pa$: Atomic number increases by $1$,so $x_2$ is a $\beta^{-}$-particle $(^{0}_{-1}e)$. Statement $(2)$ is correct.$3$. $^{234}_{91}Pa \xrightarrow{- x_3} ^{234}_{92}Z$: Atomic number increases by $1$,so $x_3$ is a $\beta^{-}$-particle. Statement $(4)$ is incorrect.$4$. $^{234}_{92}Z$ has atomic number $92$,same as $U$,so $Z$ is an isotope of uranium. Statement $(1)$ is correct.Thus,statements $(1)$,$(2)$,and $(3)$ are correct.

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