In the cyclic process shown in the figure,the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The work done by the gas in a cyclic process is equal to the area enclosed by the $P-V$ diagram.From the figure,the process forms a right-angled t

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(D) The work done by the gas in a cyclic process is equal to the area enclosed by the $P-V$ diagram.From the figure,the process forms a right-angled triangle.The base of the triangle is the change in volume: $\Delta V = 4V_1 - V_1 = 3V_1$.The height of the triangle is the change in pressure: $\Delta P = 7P_1 - P_1 = 6P_1$.The area of the triangle is given by: $	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$.Substituting the values: $	ext{Work done} = \frac{1}{2} 	imes (3V_1) 	imes (6P_1) = \frac{18}{2} P_1V_1 = 9 P_1V_1$.Thus,the work done by the gas in one cycle is $9 P_1V_1$.

In the cyclic process shown in the figure,the work done by the gas in one cycle is (in $,{P_1}{V_1}$)

Similar Questions

In a cyclic process,a gas is taken from state $A$ to $B$ via path $-I$ as shown in the indicator diagram and taken back to state $A$ from state $B$ via path $-II$. In the complete cycle

An ideal gas undergoes a four-step cycle as shown in the $P-V$ diagram below. During this cycle,in which step is heat absorbed by the gas?

Work done in the cyclic process shown in the figure is ...........

Which of the following graphs correctly represents the thermodynamic processes shown?

An indicator diagram is a ...........

Vedclass Test Series

Exam Paper Generator

Online Exam Module