In the compound HC equiv C-CH=CH_2,the hybrid | vedclass

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(C) The structure of the compound is $H-C(4) \equiv C(3)-C(2)H=C(1)H_2$.For $C-2$: It is bonded to one $H$ atom,one $C-3$ atom (via a single bond),and

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$sp^2 \& sp$

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(C) The structure of the compound is $H-C(4) \equiv C(3)-C(2)H=C(1)H_2$.For $C-2$: It is bonded to one $H$ atom,one $C-3$ atom (via a single bond),and one $C-1$ atom (via a double bond). The number of sigma bonds is $3$ and there are no lone pairs,so the hybridization is $sp^2$.For $C-3$: It is bonded to one $C-4$ atom (via a triple bond) and one $C-2$ atom (via a single bond). The number of sigma bonds is $2$ and there are no lone pairs,so the hybridization is $sp$.Therefore,the hybridization of $C-2$ and $C-3$ are $sp^2$ and $sp$ respectively.

In the compound $HC \equiv C-CH=CH_2$,the hybridization of $C-2$ and $C-3$ carbons are respectively:

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