The hybridisation of each carbon in the follo | vedclass

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Question

(A) The structure of the compound is $CH_3-C(=O)-CH_2-C \equiv N$.Let us label the carbons as follows:$(i) CH_3-$,$(ii) -C(=O)-$,$(iii) -CH_2-$,$(iv)

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$sp^3, sp^2, sp^3, sp$

Vedclass · Answer

(A) The structure of the compound is $CH_3-C(=O)-CH_2-C \equiv N$.Let us label the carbons as follows:$(i) CH_3-$,$(ii) -C(=O)-$,$(iii) -CH_2-$,$(iv) -CN$.$1$. The carbon in the methyl group $(CH_3)$ is bonded to four atoms (three $H$ and one $C$),so it is $sp^3$ hybridised.$2$. The carbonyl carbon $(C=O)$ is bonded to three atoms (one $C$ of $CH_3$,one $O$,and one $C$ of $CH_2$),so it is $sp^2$ hybridised.$3$. The methylene carbon $(CH_2)$ is bonded to four atoms (two $H$,one $C$ of $C=O$,and one $C$ of $CN$),so it is $sp^3$ hybridised.$4$. The cyano carbon $(CN)$ is bonded to two atoms (one $C$ of $CH_2$ and one $N$),so it is $sp$ hybridised.Thus,the hybridisation of carbons $(i), (ii), (iii),$ and $(iv)$ is $sp^3, sp^2, sp^3, sp$ respectively.

The hybridisation of each carbon in the following compound respectively is:
$CH_3-C(=O)-CH_2-CN$

Similar Questions

The total number of $\pi-$bond electrons in the following structure is

In the molecule $HC^{1} \equiv C^{2} - CH^{3} = CH^{4} - CH_{3}^{5}$,which carbon atom exhibits the lowest electronegativity?

How is the hybridization of carbon in an organic compound determined based on its structure? Explain.

Number of $sp$ hybridised carbon atoms in the given compound is:
$CH_2 = CH - C \equiv C - CH_2 - CN$

Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:
$H_2C=C=CH-CHO$
(Order: $sp^3 - sp^2 - sp$)

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The hybridisation of each carbon in the following compound respectively is:$CH_3-C(=O)-CH_2-CN$