In the compound M-O-H,the M-O bond will be br | vedclass

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(C) The cleavage of the $M-O-H$ bond depends on the relative electronegativity differences.If the electronegativity difference between $M$ and $O$ $(D

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$\Delta (EN)$ of $M$ and $O > \Delta (EN)$ of $O$ and $H$

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(C) The cleavage of the $M-O-H$ bond depends on the relative electronegativity differences.If the electronegativity difference between $M$ and $O$ $(Delta (EN)_{M-O})$ is greater than the electronegativity difference between $O$ and $H$ $(Delta (EN)_{O-H})$,the $M-O$ bond is more polar and will break to form $M^{+}$ and $OH^{-}$ ions.Conversely,if $\Delta (EN)_{O-H} > \Delta (EN)_{M-O}$,the $O-H$ bond will break to form $MO^{-}$ and $H^{+}$ ions.

In the compound $M-O-H$,the $M-O$ bond will be broken if

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