Diborane reacts with ammonia under different | vedclass

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Question

(B) Diborane reacts with ammonia to give different products under different reaction conditions:$1$. At low temperature: $B_2H_6 + 2NH_3 \rightarrow B

Vedclass · Accepted Answer

$B_{12}H_{12}$

Vedclass · Answer

(B) Diborane reacts with ammonia to give different products under different reaction conditions:$1$. At low temperature: $B_2H_6 + 2NH_3 \rightarrow B_2H_6 \cdot 2NH_3$ (ionic salt $[BH_2(NH_3)_2]^+[BH_4]^-$).$2$. At high temperature: $3B_2H_6 + 6NH_3 \rightarrow 2B_3N_3H_6$ (Borazine,also known as inorganic benzene).$3$. At very high temperature: $B_2H_6 + 2NH_3 \rightarrow 2(BN)_n + 6H_2$ (Boron nitride,which resembles graphite).Therefore,$B_{12}H_{12}$ is not formed in the reaction between diborane and ammonia.

Diborane reacts with ammonia under different conditions to give a variety of products. Which one among the following is not formed in these reactions?

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