$A$ transistor has a voltage gain '$A$'. If a fraction '$\beta$' of its output is fed back to the input of the transistor,then the transistor becomes an oscillator when:

If $R_C$ and $R_B$ are respectively the resistances of the collector and base sides of the circuit,and $\beta$ is the current amplification factor,then the voltage gain of a transistor amplifier in common emitter configuration is

The current amplification factor of a transistor is $50$. The input resistance when used in common emitter mode is $1 \text{ k}\Omega$. The peak value of the collector current for an a.c. input voltage of $0.01 \text{ V}$ peak is:

The value of $I_c$ for the configuration shown is in $mA$.

When the transistor is used as an amplifier,

In the figure,given that $V_{BB}$ supply can vary from $0$ to $5.0 \,V$,$V_{CC} = 5\,V$,$\beta_{dc} = 200$,$R_B = 100\,k\Omega$,$R_C = 1\,k\Omega$ and $V_{BE} = 1.0\,V$. The minimum base current and the input voltage at which the transistor will go to saturation,will be respectively: