In the circuit shown,the potential difference | vedclass

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(B) The $3 \mu F$ and $6 \mu F$ capacitors are connected in parallel. Their equivalent capacitance is $C_p = 3 \mu F + 6 \mu F = 9 \mu F$.This $C_p$ i

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$8$ volt

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(B) The $3 \mu F$ and $6 \mu F$ capacitors are connected in parallel. Their equivalent capacitance is $C_p = 3 \mu F + 6 \mu F = 9 \mu F$.This $C_p$ is in series with the $4.5 \mu F$ capacitor. The equivalent capacitance of the circuit is $C_{eq} = \frac{4.5 	imes 9}{4.5 + 9} = \frac{40.5}{13.5} = 3 \mu F$.The total charge supplied by the $12 	ext{ V}$ battery is $Q = C_{eq} V = 3 \mu F 	imes 12 	ext{ V} = 36 \mu C$.Since the $4.5 \mu F$ capacitor is in series with the combination,the charge on it is equal to the total charge $Q = 36 \mu C$.The potential difference across the $4.5 \mu F$ capacitor is $V_{4.5} = \frac{Q}{C} = \frac{36 \mu C}{4.5 \mu F} = 8 	ext{ V}$.

In the circuit shown,the potential difference across the $4.5 \mu F$ capacitor is

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