Three capacitors of capacitances $10 \mu F$,$5 \mu F$,and $20 \mu F$ are connected in series with a $14 \text{ V}$ $DC$ supply. The charge on the $5 \mu F$ capacitor is: (in $\mu C$)

What is the equivalent capacitance between $A$ and $B$ in the given circuit (in $\mu F$)?

The equivalent capacitance of three capacitors of capacitance $C_1, C_2$ and $C_3$ connected in parallel is $12$ units and their product is $C_1 \cdot C_2 \cdot C_3 = 48$. When the capacitors $C_1$ and $C_2$ are connected in parallel,the equivalent capacitance is $6$ units. Then the capacitances are:

Three capacitors,each of value $1 \ \mu\text{F}$,are connected in such a way that the resultant capacitance is $1.5 \ \mu\text{F}$. Then:

Two equal capacitors are first connected in series and then in parallel. The ratio of the equivalent capacities in the two cases will be

The equivalent capacitance between terminals $A$ and $B$ is: