In the circuit shown,the end $A$ is at potential $V_0$ and end $B$ is grounded. The electric current $I$ indicated in the circuit is

  • A
    $V_0 / R$
  • B
    $2 V_0 / R$
  • C
    $3 V_0 / R$
  • D
    $V_0 / 3 R$

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