In the given circuit diagram,find the current passing through the wire $CD$ (in ampere).

The Wheatstone bridge shown in the figure gets balanced when the carbon resistor used as $R_1$ has the colour code (Orange,Red,Brown). The resistors $R_2$ and $R_4$ are $80 \, \Omega$ and $40 \, \Omega$,respectively. Assuming that the colour code for the carbon resistors gives their accurate values,the colour code for the carbon resistor used as $R_3$ would be

Four resistances of $15\, \Omega, 12\, \Omega, 4\, \Omega$ and $10\, \Omega$ are connected in cyclic order to form a Wheatstone bridge network. The resistance that is to be connected in parallel with the resistance of $10\, \Omega$ to balance the network is ................. $\Omega$.

Two batteries,one with an $emf$ of $3\,V$ and internal resistance $1\,\Omega$,and the other with an $emf$ of $15\,V$ and internal resistance $2\,\Omega$,are connected in series with a resistance $R$ as shown in the figure. If the potential difference between points $a$ and $b$ is zero,find the resistance $R$ in $\Omega$.

In the given figure,when the galvanometer shows no deflection,the current (in $A$) flowing through the $5\,\Omega$ resistance will be:

The current through the $1 \Omega$ resistance in the following circuit is (in $A$)