In the circuit shown in the figure, neglecting the source resistance, the voltmeter and ammeter readings respectively are

What is the reason we prefer $A.C.$ voltage over $D.C.$ voltage for power transmission?

Assertion: Ohm's law cannot be applied to $a.c.$ circuits.
Reason: Resistance offered by a capacitor for an $a.c.$ source depends upon the frequency of the source.

Assertion: Long distance power transmission is done at high voltage.
Reason: At high voltage supply, power losses are less.

In the circuit shown,$L = 1 \mu H$,$C = 1 \mu F$,and $R = 1 k\Omega$. They are connected in series with an $a.c.$ source $V = V_0 \sin \omega t$ as shown. Which of the following options is/are correct?
[$A$] The frequency at which the current will be in phase with the voltage is independent of $R$.
[$B$] At $\omega \sim 0$,the current flowing through the circuit becomes nearly zero.
[$C$] At $\omega \gg 10^6 \text{ rad } s^{-1}$,the circuit behaves like a capacitor.
[$D$] The current will be in phase with the voltage if $\omega = 10^6 \text{ rad } s^{-1}$.

When an inductor of inductance $L = \frac{6}{\pi} \ H$, a capacitor of capacitance $C = \frac{50}{\pi} \ \mu F$ and a resistor of resistance $R$ are connected in series with an $AC$ supply of rms voltage $V_{rms} = 220 \ V$ and frequency $f = 50 \ Hz$, the rms current through the circuit is $I_{rms} = 440 \ mA$. Match the inductive reactance $X_L$, the capacitive reactance $X_C$, the resistance $R$, and the impedance $Z$ of the circuit given in List-$I$ with the corresponding values given in List-$II$.

List-$I$	List-$II$
$(A) \ X_L$	$(i) \ 200 \ \Omega$
$(B) \ X_C$	$(ii) \ 300 \ \Omega$
$(C) \ R$	$(iii) \ 500 \ \Omega$
$(D) \ Z$	$(iv) \ 600 \ \Omega$