In the circuit diagram shown below,the magnit | vedclass

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(D) The circuit consists of two cells of $10 	ext{ V}$ and $4 	ext{ V}$ connected in series,along with three resistors of $1 \, \Omega$,$2 \, \Omega

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$1.0 	ext{ A}$ from $a$ to $b$ via $e$

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(D) The circuit consists of two cells of $10 	ext{ V}$ and $4 	ext{ V}$ connected in series,along with three resistors of $1 \, \Omega$,$2 \, \Omega$,and $3 \, \Omega$ in series.The total electromotive force $(EMF)$ of the circuit is $E_{eq} = 10 	ext{ V} - 4 	ext{ V} = 6 	ext{ V}$ because the cells are connected in opposition (positive terminals facing each other).The total resistance of the circuit is $R_{eq} = 1 \, \Omega + 2 \, \Omega + 3 \, \Omega = 6 \, \Omega$.Using Ohm's law,the current $I$ is given by $I = E_{eq} / R_{eq} = 6 	ext{ V} / 6 \, \Omega = 1.0 	ext{ A}$.Since the $10 	ext{ V}$ cell is stronger than the $4 	ext{ V}$ cell,the current will flow in the direction dictated by the $10 	ext{ V}$ cell,which is from $a$ to $b$ via $e$.

In the circuit diagram shown below,the magnitude and direction of the flow of current respectively would be

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