In the chemical reaction given above,A and B | vedclass

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(B) The reaction sequence is as follows:$1$. The first step is the reduction of benzene diazonium chloride to benzene. This is achieved using hypophos

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$H_3PO_2$ and $CH_3CH_2Cl$

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(B) The reaction sequence is as follows:$1$. The first step is the reduction of benzene diazonium chloride to benzene. This is achieved using hypophosphorous acid $(H_3PO_2)$ and water $(H_2O)$. Thus,$A = H_3PO_2$.$2$. The second step is the Friedel-Crafts alkylation of benzene to form ethylbenzene. This requires an alkyl halide,specifically ethyl chloride $(CH_3CH_2Cl)$,in the presence of an anhydrous Lewis acid catalyst like $AlCl_3$. Thus,$B = CH_3CH_2Cl$.Therefore,$A$ is $H_3PO_2$ and $B$ is $CH_3CH_2Cl$.

In the chemical reaction given above,$A$ and $B$ respectively are:

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