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(B) For a transistor,the current gain $\alpha$ is defined as the ratio of collector current $(I_C)$ to emitter current $(I_E)$,i.e.,$\alpha = \frac{I_

Vedclass · Accepted Answer

$\beta > 1, \alpha < 1$

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(B) For a transistor,the current gain $\alpha$ is defined as the ratio of collector current $(I_C)$ to emitter current $(I_E)$,i.e.,$\alpha = \frac{I_C}{I_E}$. Since $I_E = I_C + I_B$ and $I_B > 0$,it follows that $I_C The current gain $\beta$ is defined as the ratio of collector current $(I_C)$ to base current $(I_B)$,i.e.,$\beta = \frac{I_C}{I_B}$.Since the base current $I_B$ is typically very small compared to the collector current $I_C$,the ratio $\beta = \frac{I_C}{I_B}$ is always greater than $1$.Therefore,the correct relationship is $\beta > 1$ and $\alpha < 1$.

In the case of a transistor,what is the relationship between the current gain parameters $\alpha$ and $\beta$?

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