In a transistor amplifier, AC current gain is | vedclass

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(C) The voltage gain $(A_v)$ of a transistor amplifier is given by the product of the current gain $(\beta)$ and the ratio of the load resistance $(R_

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$640$

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(C) The voltage gain $(A_v)$ of a transistor amplifier is given by the product of the current gain $(\beta)$ and the ratio of the load resistance $(R_L)$ to the input resistance $(R_{in})$.Formula: $A_v = \beta 	imes \frac{R_L}{R_{in}}$Given:$AC$ current gain $(\beta)$ = $64$Load resistance $(R_L)$ = $5400 \ \Omega$Input resistance $(R_{in})$ = $540 \ \Omega$Substituting the values:$A_v = 64 	imes \frac{5400}{540}$$A_v = 64 	imes 10$$A_v = 640$Therefore, the voltage gain is $640$.

In a transistor amplifier, $AC$ current gain is $64$, the load resistance is $5400 \ \Omega$ and the input resistance of the transistor is $540 \ \Omega$. The voltage gain is

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