In the case of a $NAND$ gate,if $A$ and $B$ are the inputs and $Y$ is the output,then:

  • A
    $Y=A \cdot B$
  • B
    $Y=\overline{A-B}$
  • C
    $Y=\overline{A+B}$
  • D
    $Y=\overline{A \cdot B}$

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