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(D) To satisfy the condition $A=1, B=1$ and $D=1$,we evaluate each circuit:$(a)$ The output is $D = A \cdot \bar{B} + \bar{A} \cdot B$. For $A=1, B=1$

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(D) To satisfy the condition $A=1, B=1$ and $D=1$,we evaluate each circuit:$(a)$ The output is $D = A \cdot \bar{B} + \bar{A} \cdot B$. For $A=1, B=1$,$D = 1 \cdot 0 + 0 \cdot 1 = 0$.$(b)$ The output is $D = \overline{(\bar{A} + B) + (A + \bar{B})}$. For $A=1, B=1$,$D = \overline{(0 + 1) + (1 + 0)} = \overline{1 + 1} = 0$.$(c)$ The output is $D = (A + B) \cdot (\bar{A} + \bar{B}) = A \cdot \bar{B} + \bar{A} \cdot B$. For $A=1, B=1$,$D = 0$.$(d)$ The output is $D = A \cdot B + \bar{A} \cdot \bar{B}$. For $A=1, B=1$,$D = 1 \cdot 1 + 0 \cdot 0 = 1 + 0 = 1$.Thus,the circuit in option $(d)$ satisfies the condition.

Which of the following circuits satisfies the logic condition $A=1, B=1$ and $D=1$?

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