In the arrangement shown in the figure,the pulleys are massless and frictionless,and the threads are inextensible. The block of mass $m_1$ will remain at rest,if

  • A
    $\frac{4}{m_1} = \frac{1}{m_2} + \frac{1}{m_3}$
  • B
    $\frac{1}{m_1} = \frac{1}{m_2} + \frac{1}{m_3}$
  • C
    $m_1 = m_2 + m_3$
  • D
    $\frac{1}{m_3} = \frac{2}{m_2} + \frac{3}{m_1}$

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