In the arrangement shown in figure, pulleys are massless and frictionless and threads are inextensible. The Block of mass $m_1$ will remain at rest, if
- A$\frac{4}{m_1}=\frac{1}{m_2}+\frac{1}{m_3}$
- B$\frac{1}{m_1}=\frac{1}{m_2}+\frac{1}{m_3}$
- C$m_1=m_2+m_3$
- D$\frac{1}{m_3}=\frac{2}{m_2}+\frac{3}{m_1}$
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- [JEE MAIN 2022]
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