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(D) In a stationary wave,the distance between a node and its nearest antinode is given by $\frac{\lambda}{4}$.Given $\frac{\lambda}{4} = 20 \ cm$,ther

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$3\pi / 2$

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(D) In a stationary wave,the distance between a node and its nearest antinode is given by $\frac{\lambda}{4}$.Given $\frac{\lambda}{4} = 20 \ cm$,therefore the wavelength $\lambda = 80 \ cm$.The phase difference $\Delta \phi$ between two particles separated by a distance $\Delta x$ is given by the formula $\Delta \phi = \frac{2\pi}{\lambda} \Delta x$.Substituting the values $\Delta x = 60 \ cm$ and $\lambda = 80 \ cm$:$\Delta \phi = \frac{2\pi}{80} 	imes 60 = \frac{120\pi}{80} = \frac{3\pi}{2}$ radians.

In stationary waves,the distance between a node and its nearest antinode is $20 \ cm$. The phase difference between two particles having a separation of $60 \ cm$ will be

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