In reaction $(1)$,$XeF_6$ undergoes complete hydrolysis to form $HF$ and $X$. In reaction $(2)$,$XeF_6$ undergoes partial hydrolysis to form $HF$,$Y$,and $Z$. The products $X, Y, Z$ respectively,are
- A$XeO_3, XeOF_4, XeO_2 F_2$
- B$XeO_3, XeO_2 F_2, XeOF_4$
- C$Xe, XeOF_4, XeO_2 F_2$
- D$XeO_3, O_2, XeO_2 F_2$
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Similar Questions
What is the atomic number $(Z)$ of the noble gas that reacts with fluorine?
Easy
View SolutionWhich one of the following noble gas has an unusual property of diffusing through materials such as rubber,glass,or plastic?
Give the formula and describe the structure of a noble gas species which is isostructural with:
$(i)$ $ICl_{4}^{-}$
$(ii)$ $IBr_{2}^{-}$
$(iii)$ $BrO_{3}^{-}$
$(i)$ $ICl_{4}^{-}$
$(ii)$ $IBr_{2}^{-}$
$(iii)$ $BrO_{3}^{-}$
Medium
View SolutionIn the following reaction,find the values of $a, b, p, q, r$ and $s$:
$a XeF_4 + b H_2O \rightarrow p Xe + q XeO_3 + r HF + s O_2$
$a XeF_4 + b H_2O \rightarrow p Xe + q XeO_3 + r HF + s O_2$
Which one of the following does not exist?
$(i)$ $XeOF_{4}$
$(ii)$ $NeF_{2}$
$(iii)$ $XeF_{2}$
$(iv)$ $XeF_{6}$
$(i)$ $XeOF_{4}$
$(ii)$ $NeF_{2}$
$(iii)$ $XeF_{2}$
$(iv)$ $XeF_{6}$
Easy
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