In quadrilateral ABCD, one of its diagonals A | vedclass

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(C) The area of a quadrilateral can be calculated by dividing it into two triangles using a diagonal.Area of quadrilateral $ABCD = 	ext{Area}(	riang

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(C) The area of a quadrilateral can be calculated by dividing it into two triangles using a diagonal.Area of quadrilateral $ABCD = 	ext{Area}(	riangle ABC) + 	ext{Area}(	riangle ADC)$.Area of $	riangle ABC = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 20 	imes 8 = 80 \, cm^2$.Area of $	riangle ADC = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 20 	imes 12 = 120 \, cm^2$.Total Area $= 80 + 120 = 200 \, cm^2$.

In quadrilateral $ABCD$, one of its diagonals $AC$ measures $20 \, cm$. The altitudes on $AC$ from vertices $B$ and $D$ are $8 \, cm$ and $12 \, cm$ respectively. Find the area of quadrilateral $ABCD$ in $cm^2$.

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