In the photoelectric effect,if the intensity | vedclass

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(D) According to Einstein's photoelectric equation,the maximum kinetic energy of photoelectrons is given by $K_{\max} = h
u - \phi$,where $h$ is Plan

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(D) According to Einstein's photoelectric equation,the maximum kinetic energy of photoelectrons is given by $K_{\max} = h
u - \phi$,where $h$ is Planck's constant,$
u$ is the frequency of incident light,and $\phi$ is the work function of the metal.This equation shows that $K_{\max}$ depends only on the frequency of the incident light and the nature of the material (work function).Intensity of light affects the number of photons incident per unit area per unit time,which in turn affects the number of photoelectrons emitted (photoelectric current),but it does not affect the energy of individual photoelectrons.Therefore,if the intensity of light is doubled,the maximum kinetic energy of the photoelectrons remains unchanged.

In the photoelectric effect,if the intensity of light is doubled,then the maximum kinetic energy of the photoelectrons will become:

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