The stopping potential required to reduce the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of emitted photoelectrons is given by: $K_{max} = h
u - \Ph

Vedclass · Accepted Answer

increases linearly with the frequency of the incident light.

Vedclass · Answer

(D) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of emitted photoelectrons is given by: $K_{max} = h
u - \Phi$,where $h$ is Planck's constant,$
u$ is the frequency of incident light,and $\Phi$ is the work function of the metal.Since the stopping potential $(V_s)$ is related to the maximum kinetic energy by $K_{max} = eV_s$,we have: $eV_s = h
u - \Phi$.Rearranging for $V_s$,we get: $V_s = (h/e)
u - (\Phi/e)$.This equation represents a linear relationship between the stopping potential $(V_s)$ and the frequency $(
u)$ of the incident light,where the slope is $(h/e)$ and the intercept is $-(\Phi/e)$.Therefore,the stopping potential increases linearly with the frequency of the incident light.

The stopping potential required to reduce the photoelectric current to zero is . . . . . .

Similar Questions

An isolated metallic sphere is illuminated by light of $4\,eV$ photon energy. If the work function of the metal is $2\,eV$,then the minimum potential of the sphere so that no photoelectrons are ejected is ................ $V$.

In a photoelectric experiment, the wavelength of the light incident on the metal is changed from $200 \, nm$ to $400 \, nm$. The decrease in the stopping potential is close to [Use $hc = 1240 \, eV \cdot nm$ where $h$ is Planck's constant and $c$ is the velocity of light]. (in $ \, V$)

Sodium and copper have work functions $2.3 \ eV$ and $4.5 \ eV$ respectively. Then the ratio of their threshold wavelengths is nearest to

The threshold wavelength for sodium is $6 \times 10^{-7} \, m$. Photoemission occurs for light of wavelength $\lambda$ if:

Vedclass Test Series

Exam Paper Generator

Online Exam Module