In Melde's experiment in the transverse mode,the frequency of the tuning fork and the frequency of the waves in the strings are in the ratio

If two progressive sound waves represented by $y_1 = 3 \sin(250 \pi t)$ and $y_2 = 2 \sin(260 \pi t)$ (where displacement is in metre and time is in second) superimpose,then the time interval between two successive maximum intensities is (in $s$)

During the superposition of two waves of nearly equal frequencies,the beat frequency is defined as the:

Two tuning forks $A$ and $B$ are sounded together giving rise to $8$ beats in $2$ s. When fork $A$ is loaded with wax,the beat frequency is reduced to $4$ beats in $2$ s. If the original frequency of tuning fork $B$ is $380$ Hz,then the original frequency of tuning fork $A$ is . . . . . . Hz.

$A$ source of frequency $\nu$ gives $5$ beats/second when sounded with a source of frequency $200 \;Hz$. The second harmonic of frequency $2\nu$ of the source gives $10$ beats/second when sounded with a source of frequency $420 \;Hz$. The value of $\nu$ is .... $Hz$.

Two sources of sound are emitting progressive waves $y_1 = 4 \sin(710 \pi t)$ and $y_2 = 3 \sin(702 \pi t)$. The sources are placed close to each other. The number of beats heard per second and the intensity ratio between waxing and waning are respectively: