Two tuning forks A and B are sounded together | vedclass

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(A) The beat frequency is the number of beats per second. Initially,$8$ beats in $2$ s means the beat frequency is $f_{beat} = 8/2 = 4$ Hz.This implie

Vedclass · Accepted Answer

$384$

Vedclass · Answer

(A) The beat frequency is the number of beats per second. Initially,$8$ beats in $2$ s means the beat frequency is $f_{beat} = 8/2 = 4$ Hz.This implies $|f_A - f_B| = 4$ Hz.Given $f_B = 380$ Hz,so $|f_A - 380| = 4$,which means $f_A = 384$ Hz or $f_A = 376$ Hz.When tuning fork $A$ is loaded with wax,its frequency $f_A$ decreases.After loading,the new beat frequency is $4$ beats in $2$ s,which is $f'_{beat} = 4/2 = 2$ Hz.If $f_A$ was $376$ Hz,loading it would decrease it further away from $380$ Hz,increasing the beat frequency.If $f_A$ was $384$ Hz,loading it would decrease it towards $380$ Hz,reducing the beat frequency to $2$ Hz.Therefore,the original frequency of tuning fork $A$ must be $384$ Hz.

Two tuning forks $A$ and $B$ are sounded together giving rise to $8$ beats in $2$ s. When fork $A$ is loaded with wax,the beat frequency is reduced to $4$ beats in $2$ s. If the original frequency of tuning fork $B$ is $380$ Hz,then the original frequency of tuning fork $A$ is . . . . . . Hz.

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