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Question

(b) : In a stable population, for a gene with two alleles, &lsquo;$A$&rsquo; (dominant) and &lsquo;$a$&rsquo; (recessive), if the frequency of &lsquo;

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$2pq$

Vedclass · Answer

(b) : In a stable population, for a gene with two alleles, &lsquo;$A$&rsquo; (dominant) and &lsquo;$a$&rsquo; (recessive), if the frequency of &lsquo;$A$&rsquo; is $p$ and the frequency of &lsquo;$a$&rsquo; is $q$, then the frequencies of the three possible genotypes ($AA, Aa$ and $aa$) can be expressed by the Hardy&shy; Weinberg equation :

$p^2 + 2pq + q^2 = 1$

where $p^2$ = Frequency of $AA$ (homozygous dominant) individuals

$q^2$ = Frequency of $aa$ (homozygous recessive) individuals

$2pq$ = Frequency of $Aa$ (heterozygous) individuals

In HardyWeinberg equation, the frequency of heterozygous individual is represented by

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