In a population of 1000 individuals,490 belon | vedclass

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Question

(D) Total population $(N)$ = $1000$. Number of $MM$ individuals = $490$. Number of $Mm$ individuals = $420$. Number of $mm$ individuals = $1000 - (490

Vedclass · Accepted Answer

$0.3$

Vedclass · Answer

(D) Total population $(N)$ = $1000$. Number of $MM$ individuals = $490$. Number of $Mm$ individuals = $420$. Number of $mm$ individuals = $1000 - (490 + 420) = 1000 - 910 = 90$. Frequency of allele $m$ $(q)$ can be calculated as: $q = \frac{(	ext{Number of } mm 	ext{ individuals} 	imes 2) + (	ext{Number of } Mm 	ext{ individuals})}{2 	imes 	ext{Total population}}$ $q = \frac{(90 	imes 2) + 420}{2 	imes 1000} = \frac{180 + 420}{2000} = \frac{600}{2000} = 0.3$. Therefore,the frequency of allele $m$ is $0.3$.

In a population of $1000$ individuals,$490$ belong to genotype $MM$,$420$ to $Mm$,and the remaining to $mm$. Based on this data,the frequency of allele $m$ in the population is . . . . . . .

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