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Question

(A) The nitro group $(-NO_2)$ is a strong electron-withdrawing group due to its $-I$ and $-M$ effects. It withdraws electron density from the benzene

Vedclass · Accepted Answer

decreases electron density at ortho and para positions

Vedclass · Answer

(A) The nitro group $(-NO_2)$ is a strong electron-withdrawing group due to its $-I$ and $-M$ effects. It withdraws electron density from the benzene ring,specifically from the ortho $(o)$ and para $(p)$ positions through resonance. As a result,the electron density at the $o$ and $p$ positions decreases significantly compared to the meta $(m)$ positions. Since the electrophile is electron-deficient,it prefers to attack the position with relatively higher electron density,which is the meta position. Therefore,the nitro group is meta-directing.

In electrophilic aromatic substitution reaction,the nitro group is meta-directing because it

Similar Questions

Xylenes on oxidation with acidic $KMnO_4$ give:

The major product formed in the following reaction sequence is:
$C_6H_5-CHBr-CH_2Br$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH}$ $\xrightarrow[(iii) \text{Red hot iron tube}, 873 K]{}$

For the given compounds,what is the decreasing order of the rate of electrophilic aromatic substitution?

The order of decreasing reactivity towards an electrophilic reagent,for the following compounds,is:
$(i) \text{ Benzene} \quad (ii) \text{ Toluene} \quad (iii) \text{ Chlorobenzene} \quad (iv) \text{ Phenol}$

Point out the wrong statement in relation to the structure of benzene.

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