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(D) Given: $\beta = 20$, $I_{E} = 7 \,mA$.We know that the current gain in common emitter mode is defined as $\beta = \frac{I_{C}}{I_{B}}$.Also, the r

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$20$

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(D) Given: $\beta = 20$, $I_{E} = 7 \,mA$.We know that the current gain in common emitter mode is defined as $\beta = \frac{I_{C}}{I_{B}}$.Also, the relationship between emitter current, collector current, and base current is $I_{E} = I_{C} + I_{B}$, which implies $I_{B} = I_{E} - I_{C}$.Substituting $I_{B}$ in the gain formula: $\beta = \frac{I_{C}}{I_{E} - I_{C}}$.Rearranging the equation: $20 = \frac{I_{C}}{7 - I_{C}}$.$20(7 - I_{C}) = I_{C}$.$140 - 20I_{C} = I_{C}$.$140 = 21I_{C}$.$I_{C} = \frac{140}{21} = \frac{20}{3} \,mA$.

In common emitter mode of a transistor, the d.c. current gain is $20$, and the emitter current is $7 \,mA$. The collector current is (in $/ 3 \,mA$)

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