In the chromyl chloride test,the oxidation st | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The chromyl chloride test is used for the detection of chloride ions $(Cl^-)$. In this test,a chloride salt is heated with potassium dichromate $(

Vedclass · Accepted Answer

Remains constant

Vedclass · Answer

(D) The chromyl chloride test is used for the detection of chloride ions $(Cl^-)$. In this test,a chloride salt is heated with potassium dichromate $(K_2Cr_2O_7)$ and concentrated sulfuric acid $(H_2SO_4)$. The reaction produces chromyl chloride $(CrO_2Cl_2)$ vapors. The chemical equation is: $K_2Cr_2O_7 + 4NaCl + 6H_2SO_4 \rightarrow 2KHSO_4 + 4NaHSO_4 + 2CrO_2Cl_2 + 3H_2O$. In $K_2Cr_2O_7$,the oxidation state of $Cr$ is $+6$. In the product $CrO_2Cl_2$,the oxidation state of $Cr$ is calculated as: $x + 2(-2) + 2(-1) = 0$,which gives $x - 4 - 2 = 0$,so $x = +6$. Since the oxidation state of $Cr$ is $+6$ in both the reactant $(K_2Cr_2O_7)$ and the product $(CrO_2Cl_2)$,it remains constant.

In the chromyl chloride test,the oxidation state of $Cr$ changes from:

Similar Questions

$LiCoO_2$ crystallizes in a rhombohedral structure. Consider a situation where $50\%$ lithium $(Li)$ is extracted from the lattice. To keep the crystal electrically neutral,the change in the average oxidation state of $Co$ is

What is the oxidation number of $Cl$ in $HClO_4$ and $HClO_3$?

Calculate the oxidation number of $C$ in glucose $(C_{6}H_{12}O_{6})$.

In acidic medium,$H_2O_2$ changes $Cr_2O_7^{2-}$ to $CrO_5$ which has two peroxy linkages. The oxidation state of $Cr$ in $CrO_5$ is

An acidic solution of sodium thiosulfate is unstable because in thiosulfate,the two sulfur atoms have different oxidation states of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module