In the Cannizzaro reaction given below:2PhCHO | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The mechanism of the Cannizzaro reaction involves the nucleophilic attack of the hydroxide ion on the carbonyl carbon to form a di-anion intermedi

Vedclass · Accepted Answer

the transfer of hydride to the carbonyl group

Vedclass · Answer

(A) The mechanism of the Cannizzaro reaction involves the nucleophilic attack of the hydroxide ion on the carbonyl carbon to form a di-anion intermediate.The rate-determining step (slowest step) is the transfer of a hydride ion $(H^-)$ from the di-anion intermediate to the carbonyl carbon of a second molecule of aldehyde.This hydride transfer results in the formation of a carboxylate ion and an alkoxide ion,which subsequently undergo proton exchange to yield the final products,$PhCH_2OH$ and $PhCOO^-$.

In the Cannizzaro reaction given below:
$2PhCHO \xrightarrow{:\mathop{O}\limits^{\ominus}H} PhCH_2OH + PhC\mathop{O_2^{\ominus}}\limits$
the slowest step is:

Similar Questions

Aldol condensation will not take place in

Identify the product of the following reaction:
$CH_3-CO-CH_2-CH_2-CH_2-CHO \xrightarrow{NaOH, \Delta} \text{Product}$

Iodoform test is not given by

What are $Y$ and $Z$ respectively in the given reaction sequence?

The value of $x$ in the above reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the Cannizzaro reaction given below:$2PhCHO \xrightarrow{:\mathop{O}\limits^{\ominus}H} PhCH_2OH + PhC\mathop{O_2^{\ominus}}\limits$the slowest step is: