In the Brown ring complex [Fe(H_2O)_5NO]SO_4, | vedclass

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Question

(A) In the Brown ring complex $[Fe(H_2O)_5NO]SO_4$,the $NO$ ligand exists as the nitrosonium ion $(NO^+)$.Let the oxidation state of $Fe$ be $x$.The c

Vedclass · Accepted Answer

$+1$

Vedclass · Answer

(A) In the Brown ring complex $[Fe(H_2O)_5NO]SO_4$,the $NO$ ligand exists as the nitrosonium ion $(NO^+)$.Let the oxidation state of $Fe$ be $x$.The charge on $H_2O$ is $0$,and the charge on $SO_4$ is $-2$.Thus,$x + 5(0) + 1(+1) + (-2) = 0$.$x + 1 - 2 = 0$.$x - 1 = 0$.$x = +1$.Therefore,the oxidation state of $Fe$ is $+1$.

In the Brown ring complex $[Fe(H_2O)_5NO]SO_4$,the primary valency (oxidation state) of $Fe$ is:

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