In an extrinsic semiconductor,the number densities of holes and electrons are ${N_p}$ and ${N_e}$ respectively. Then:

  • A
    ${N_p} > {N_e}$
  • B
    ${N_p} = {N_e}$
  • C
    ${N_p} < {N_e}$
  • D
    ${N_p} > {N_e}$ or ${N_p} < {N_e}$ depends on the type of impurity.

Explore More

Similar Questions

The electron concentration in an $n$-type semiconductor is the same as the hole concentration in a $p$-type semiconductor. An external electric field is applied across each of them. Compare the currents in them.

Which of the following is an inorganic compound semiconductor?

In $n$-type semiconductor,electrons are majority charge carriers,but it does not show any negative charge. The reason is:

If $n_e$ and $n_h$ are electron and hole concentrations in an extrinsic semiconductor and $n_i$ is the intrinsic carrier concentration,then:

$A$ semiconductor doped with a donor impurity is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo