$A$ person measures the mass of $3$ different particles as $435.42 \ g$,$226.3 \ g$,and $0.125 \ g$. According to the rules for arithmetic operations with significant figures,the sum of the masses of the $3$ particles will be: (in $g$)

Match the numbers in Column-$I$ with the number of significant figures in Column-$II$.

Column-$I$	Column-$II$
$(1)$ $2.85 \times 10^{26} \ kg$	$(a)$ $1$
$(2)$ $0.009 \ m^2$	$(b)$ $2$
$(3)$ $0.060 \ s$	$(c)$ $3$

Round off the value $2.845$ to three significant figures.

For the four sets of three measured physical quantities as given below,which of the following options is correct?
$(i)$ $A_{1}=24.36, B_{1}=0.0724, C_{1}=256.2$
$(ii)$ $A_{2}=24.44, B_{2}=16.082, C_{2}=240.2$
$(iii)$ $A_{3}=25.2, B_{3}=19.2812, C_{3}=236.183$
$(iv)$ $A_{4}=25, B_{4}=236.191, C_{4}=19.5$

From the point of view of significant figures,which of the following is/are correct?
$(i)\ 11.3 \ cm + 4 \ cm = 15.3 \ cm$
$(ii)\ 4.53 \ m - 1.2 \ m = 3.3 \ m$
$(iii)\ 5.45 \ kg - 3.2 \ kg = 2.25 \ kg$
$(iv)\ 84.8 \ cm + 48.6 \ cm = 133 \ cm$

For an experimental expression $y=\frac{32.3 \times 1125}{27.4}$,where all the digits are significant. Then to report the value of $y$,we should write $:-$