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(A) When electrons pass through a narrow slit of width $'d'$,they undergo diffraction due to their wave nature. The intensity distribution of the diff

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(A) When electrons pass through a narrow slit of width $'d'$,they undergo diffraction due to their wave nature. The intensity distribution of the diffraction pattern on the screen is given by the single-slit diffraction formula,where the intensity $I$ is proportional to $N$. The central maximum occurs at $y = 0$. The first minima occur at positions given by $y = \pm \frac{\lambda D}{d}$. Since the slit width $'d'$ is comparable to the de-Broglie wavelength $\lambda$,the diffraction pattern is spread out. The graph representing this intensity distribution shows a central peak at $y = 0$ with secondary maxima on either side,which corresponds to the pattern shown in Graph $A$.

Similar Questions

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