In an equilibrium reaction for which $\Delta G^o = 0$,the equilibrium constant $K = $

  • A
    $0$
  • B
    $1$
  • C
    $2$
  • D
    $10$

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The correct relationship between the equilibrium constant $(K)$ and the standard Gibbs free energy change $(\Delta G^o)$ for a reaction is .......

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Consider the reaction $X \rightleftharpoons Y$ at $300 \text{ K}$. If $\Delta H^\circ$ and $K$ are $28.40 \text{ kJ mol}^{-1}$ and $1.8 \times 10^{-7}$ at the same temperature,then the magnitude of $\Delta S^\circ$ for the reaction in $\text{J K}^{-1} \text{ mol}^{-1}$ is . . . . . . . (Nearest integer) (Given: $R = 8.3 \text{ J K}^{-1} \text{ mol}^{-1}$,$\ln 10 = 2.3$,$\log 3 = 0.48$,$\log 2 = 0.30$)

If the equilibrium constant of a process is $3.8 \times 10^{-3}$ at $25^{\circ} C$,what is the standard free energy change of the process? $(R = 8.314 \ J \ mol^{-1} \ K^{-1}, \log 0.0038 = -2.42)$

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