In an ellipse,the distance between its foci i | vedclass

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(C) The distance between the foci of an ellipse is given by $2ae = 6$,which implies $ae = 3$.The length of the minor axis is given by $2b = 8$,which i

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$\frac{3}{5}$

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(C) The distance between the foci of an ellipse is given by $2ae = 6$,which implies $ae = 3$.The length of the minor axis is given by $2b = 8$,which implies $b = 4$.For an ellipse,the relationship between the semi-major axis $a$,semi-minor axis $b$,and eccentricity $e$ is $b^2 = a^2(1 - e^2)$,which can be written as $b^2 = a^2 - (ae)^2$.Substituting the known values: $4^2 = a^2 - 3^2$.$16 = a^2 - 9$.$a^2 = 25$,so $a = 5$.Since $ae = 3$,we have $5e = 3$,which gives $e = \frac{3}{5}$.

In an ellipse,the distance between its foci is $6$ and its minor axis is $8$. Then its eccentricity is

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