In an elevator,a spring clock of time period | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The time period of a spring-mass system is given by $T_S = 2 \pi \sqrt{\frac{m}{k}}$. This formula does not contain the acceleration due to gravit

Vedclass · Accepted Answer

$T_S$ remains same,$T_P$ decreases

Vedclass · Answer

(C) The time period of a spring-mass system is given by $T_S = 2 \pi \sqrt{\frac{m}{k}}$. This formula does not contain the acceleration due to gravity $g$,so $T_S$ remains unchanged when the elevator accelerates.The time period of a simple pendulum is given by $T_P = 2 \pi \sqrt{\frac{\ell}{g_{eff}}}$.When the elevator accelerates upwards with acceleration $a$,the effective acceleration due to gravity becomes $g_{eff} = g + a$.Since $g_{eff} > g$,the denominator increases,which causes the time period $T_P$ to decrease.Therefore,$T_S$ remains the same and $T_P$ decreases.

In an elevator,a spring clock of time period $T_S$ (mass attached to a spring) and a pendulum clock of time period $T_P$ are kept. If the elevator accelerates upwards,what happens to their time periods?

Similar Questions

An object of mass $3 \,kg$ is tied by a string of negligible mass to a ceiling and held such that the string is taut. The object is released suddenly such that the string remains taut. Its acceleration when released is (acceleration due to gravity $= 10 \,ms^{-2}$) (in $\,ms^{-2}$)

$A$ simple pendulum with length $100\,cm$ and bob of mass $250\,g$ is executing $S$.$H$.$M$. of amplitude $10\,cm$. The maximum tension in the string is found to be $\frac{x}{40}\,N$. The value of $x$ is $..........$.

$A$ simple pendulum keeps correct time at $0^{\circ}C$. At $25^{\circ}C$,it loses $12.5 \, s$ in a day. What is the coefficient of linear expansion of the metal of the pendulum?

$A$ uniform rod of length $1.8 \,m$ suspended by an end is made to undergo small oscillations. Find the length of the simple pendulum having the mass and time period equal to that of the rod. (in $\,m$)

$A$ simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration $a$. The time period is given by $T = 2\pi \sqrt{\frac{l}{g'}}$,where $g'$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module