A simple pendulum is suspended from the roof | vedclass

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Question

(D) When a trolley moves with a horizontal acceleration $a$,a pseudo force $ma$ acts on the bob of the pendulum in the direction opposite to the accel

Vedclass · Accepted Answer

$\sqrt{g^2 + a^2}$

Vedclass · Answer

(D) When a trolley moves with a horizontal acceleration $a$,a pseudo force $ma$ acts on the bob of the pendulum in the direction opposite to the acceleration of the trolley.The effective acceleration due to gravity $g'$ is the vector sum of the acceleration due to gravity $g$ (acting downwards) and the pseudo acceleration $a$ (acting horizontally).Since these two vectors are perpendicular to each other,the magnitude of the effective acceleration $g'$ is given by:$g' = \sqrt{g^2 + a^2}$Thus,the correct option is $D$.

$A$ simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration $a$. The time period is given by $T = 2\pi \sqrt{\frac{l}{g'}}$,where $g'$ is equal to:

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