In an adiabatic process,no transfer of heat t | vedclass

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(C) For free expansion,the external pressure $P_{ext} = 0$,therefore work done $W = -P_{ext} \Delta V = 0$. For an adiabatic process,the heat exchange

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$q=0, \Delta T=0, W=0$

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(C) For free expansion,the external pressure $P_{ext} = 0$,therefore work done $W = -P_{ext} \Delta V = 0$. For an adiabatic process,the heat exchange $q = 0$. According to the first law of thermodynamics,$\Delta U = q + W$. Since $q = 0$ and $W = 0$,the change in internal energy $\Delta U = 0$. For an ideal gas,internal energy is a function of temperature only $(U = f(T))$,so $\Delta U = 0$ implies $\Delta T = 0$. Thus,for free expansion of an ideal gas under adiabatic conditions,$q=0, \Delta T=0, W=0$.

In an adiabatic process,no transfer of heat takes place between the system and surroundings. Choose the correct option for the free expansion of an ideal gas under adiabatic conditions from the following:

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