In an $a.c.$ circuit,the voltage applied is $E = E_o \sin \omega t$. The resulting current in the circuit is $I = I_o \sin \left( \omega t - \frac{\pi}{2} \right)$. The power consumption in the circuit is given by:

  • A
    $P = \sqrt{3} E_o I_o$
  • B
    $P = \frac{E_o I_o}{\sqrt{2}}$
  • C
    $P = 0$
  • D
    $P = \frac{E_o I_o}{2}$

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