In an $NPN$ transistor circuit,the collector current is $10 \,mA$. If $90\%$ of the electrons emitted reach the collector,the emitter current $(i_E)$ and base current $(i_B)$ are given by
- A$i_E = -1 \,mA, i_B = 9 \,mA$
- B$i_E = 9 \,mA, i_B = -1 \,mA$
- C$i_E = 1 \,mA, i_B = 11 \,mA$
- D$i_E = 11 \,mA, i_B = 1 \,mA$
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